downpunxx@fedia.io to Lemmy Shitpost@lemmy.world · 5 months agomath checks outfedia.ioimagemessage-square106fedilinkarrow-up11.6Karrow-down112
arrow-up11.59Karrow-down1imagemath checks outfedia.iodownpunxx@fedia.io to Lemmy Shitpost@lemmy.world · 5 months agomessage-square106fedilink
minus-squareegeres@lemmy.worldlinkfedilinkarrow-up15arrow-down1·edit-25 months agoEehrm, acktually, the tweet is wrong 🤓 You can always be getting a result above average in a series of numbers as long as the nth number is significantly greater than the previous ones. For example, f(x) = x^2 would always be above average for every next number
minus-squarelseif@sopuli.xyzlinkfedilinkarrow-up3·5 months agoif it is considering the average for all of history, then the rate of change would just have to be consistently greater than 0, right ?
minus-squareSeasoned_Greetings@lemm.eelinkfedilinkarrow-up3·5 months agoI like the idea of an infinitely exponentially growing base of users seeking help from some poor call center
minus-squareb000rg@midwest.sociallinkfedilinkEnglisharrow-up3·5 months agoThis honestly sounds like it could be the basis for a novella
minus-squareMigmog@lemm.eelinkfedilinkarrow-up2·5 months agoIt sounds like something that happens regularly during an update to software with a lot of users.
Eehrm, acktually, the tweet is wrong 🤓
You can always be getting a result above average in a series of numbers as long as the nth number is significantly greater than the previous ones. For example, f(x) = x^2 would always be above average for every next number
if it is considering the average for all of history, then the rate of change would just have to be consistently greater than 0, right ?
I like the idea of an infinitely exponentially growing base of users seeking help from some poor call center
This honestly sounds like it could be the basis for a novella
It sounds like something that happens regularly during an update to software with a lot of users.
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